Question

Surface charge density of a sphere of a radius 10 cm is 8.85 x 10 - 8C / m². Potential at the centre of the
sphere is​

Answer 1

Answer :-

1000 V

Explanation :-

Given conditions,

Radius(r) = 10 cm

= 0.1 m

Surface charge density(σ) = 8.85 × 10⁻⁸ C/m².

Using the formula,

σ = Charge / Surface Area

∴ 8.85 × 10⁻⁸ = Q/4π(0.1)²

∴ Q = 8.85 × 10⁻⁸ × 4π × R × R

∴ Q/4πR = 8.85 × 10⁻⁸ × R    ....eq. (I)

Using the formula,

Potential = kQ / R, where R is the radius of the sphere.

∴ V = Q/4πε₀R

∴ V = Q/πR × 1/ε₀

∴ V =  8.85 × 10⁻⁸ × R ÷ 8.85 × 10⁻¹²

∴ V = 10⁴R

∴ V = 10000R

∴ V = 10000 × 0.1

∴ V = 1000 V

Thanks ...