Question

Surjeet drove 3 hours longer than Shilpa at an average speed 3 kms per hour faster
than Shilpa. Harsh drove 6 hours 6 hours longer than Shilpa at an average speed 6
kms per hour faster than Shilpa. If Surjeet drive 40 kms more than Shilpa, then how
many more kms did Harsh drive more than Shilpa?

Answer 1

Harsh drive 98 km more than Shilpa

Step-by-step explanation:

shilpa speed = S km/hr

Shipa time = T hr

Distance = ST km

Surjeet drove 3 hours longer than Shilpa at an average speed 3 kms per hour faster than shilpa

Surjeet Distance = (S +3)(T+3) = ST + 3(S+T) + 9

ST + 3(S+T) + 9 = ST + 40

3(S+T) = 31

Harsh drove 6 hours 6 hours longer than Shilpa at an average speed 6 kms per hour faster than Shilpa

Harsha Distance = (S +6)(T+6) = ST + 6(S+T) + 36

ST + 2×3(S+T) + 36

ST + 2×31 + 36

ST + 98

Harsh drive 98 km more than Shilpa

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