Math, asked by Vindhu2llair, 1 year ago

sushil is now 4 times as old as sunil .five years ago sushil was 7 times as old as sunil then. what is the present ages of each of them

Answers

Answered by mysticd
64
at present
sunil age = x years
sushil age =4x years

5 years ago
sunil age = x-5
sushil age =( 4x-5)years

five years ago sushil was 7 times as old as sunil
4x-5 = 7(x-5)
4x-5 =7x-35
-5+35 = 7x-4x
30 =3x
3x= 30

x= 30/3
x=10
therefore
at present
sunil age = x =10 years
sushil age = 4x =4*10 =40 years
Answered by ayeshaajaz2009
0

Answer:

sushil age = 40 years

Step-by-step explanation:

at present

sunil age = x years

sushil age =4x years

5 years ago

sunil age = x-5

sushil age =( 4x-5)years

five years ago sushil was 7 times as old as sunil

4x-5 = 7(x-5)

4x-5 =7x-35

-5+35 = 7x-4x

30 =3x

3x= 30

x= 30/3

x=10

therefore

at present

sunil age = x =10 years

sushil age = 4x =4*10 =40 years

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