sushil is now 4 times as old as sunil .five years ago sushil was 7 times as old as sunil then. what is the present ages of each of them
Answers
Answered by
64
at present
sunil age = x years
sushil age =4x years
5 years ago
sunil age = x-5
sushil age =( 4x-5)years
five years ago sushil was 7 times as old as sunil
4x-5 = 7(x-5)
4x-5 =7x-35
-5+35 = 7x-4x
30 =3x
3x= 30
x= 30/3
x=10
therefore
at present
sunil age = x =10 years
sushil age = 4x =4*10 =40 years
sunil age = x years
sushil age =4x years
5 years ago
sunil age = x-5
sushil age =( 4x-5)years
five years ago sushil was 7 times as old as sunil
4x-5 = 7(x-5)
4x-5 =7x-35
-5+35 = 7x-4x
30 =3x
3x= 30
x= 30/3
x=10
therefore
at present
sunil age = x =10 years
sushil age = 4x =4*10 =40 years
Answered by
0
Answer:
sushil age = 40 years
Step-by-step explanation:
at present
sunil age = x years
sushil age =4x years
5 years ago
sunil age = x-5
sushil age =( 4x-5)years
five years ago sushil was 7 times as old as sunil
4x-5 = 7(x-5)
4x-5 =7x-35
-5+35 = 7x-4x
30 =3x
3x= 30
x= 30/3
x=10
therefore
at present
sunil age = x =10 years
sushil age = 4x =4*10 =40 years
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