Math, asked by apple786, 1 year ago

sushil Kumar borrowed a loan on his policy at 9% per annum . if he paid 594rs as interest after 5/2 years.​

Answers

Answered by bhagyashreechowdhury
0

Given:

Sushil Kumar borrowed a loan on his policy at 9% per annum.

If he paid Rs. 594 as interest after 5/2 years.​

To find:

The sum of loan borrowed by him

Solution:

Let's assume "P" represents the sum of loan borrowed by Sushil Kumar.

The rate of interest, R = 9% p.a.

The interest he paid, S.I. = Rs. 594

The no. of years, T = \frac{5}{2} \:years

We have the formula of simple interest as:

\boxed{\bold{Simple \:Interest = \frac{P\times R \times T}{100}  }}

On substituting the values of S.I., R & T in the above formula, we get

594 = \frac{P\:\times\: 9\: \times\: \frac{5}{2} }{100}

\implies 594 \times 100 = P\:\times\: 9\: \times\: \frac{5}{2}

\implies 66 \times 20 = P\:\times\: 1\: \times\: \frac{1}{2}

\implies P = 66\: \times \:20\:\times\: 2

\implies \bold{P = 2640}

Thus, the sum of loan borrowed by Sushil Kumar is → Rs. 2640.

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Answered by rajmathurr1992
2

Answer:

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