Question

Sussex County received 43 inches of
rainfall this year. The percent error in the
local meteorologist’s rainfall prediction
was about 18.02%. What are two
possible values for the meteorologist’s
prediction?

Answer 1

||✪✪ GIVEN ✪✪||

• Sussex County received 43 inches of rainfall this year.
• The percent error in the local meteorologist’s rainfall prediction was about 18.02%.

|| ✰✰ ANSWER ✰✰ ||

Let in Case 1 , we Have, percent error in the local meteorologist’s rainfall prediction was about 18.02% High.

So, we can Say That,

→ Total Rainfall This year was = 100 + 18.02 = 118.02% .

And, Value of This is Given as 43 inches.

So,

→ 118.02% ------------------- 43inches .

→ 1% -------------------------- (43/118.02) inches.

→ 100% ---------------------- (43/118.02) * 100 = 36.43 inches.

______________________________

In Case 2, Now, Let us Assume That, percent error in the local meteorologist’s rainfall prediction was about 18.02% Low..

So,

→ Total Rainfall This year was = 100 - 18.02 = 81.98% .

And, Value of This is Given as 43 inches.

So,

→ 81.98% ------------------- 43inches .

→ 1% -------------------------- (43/81.98) inches.

→ 100% ---------------------- (43/81.98) * 100 = 52.45 inches.

Hence, we can say That, two

Hence, we can say That, twopossible values for the meteorologist’s

Hence, we can say That, twopossible values for the meteorologist’sprediction were 36.43 inches & 52.45 inches.

Answer 2

Refer the attachment.....