Question

Suvad had to make a model of a cylindrical kaleidoscope for her science project. She wanted to use chart paper to make the curved surface of the kaleidoscope. What would be the area of chart paper required by him, if he wanted to make a kaleidoscope of length 25 cm with 3.5 cm radius ? You have take $\pi = \dfrac{22}{7}$​

Answer 1

$\Large{\mathfrak{\underline{Answer:}}} \\ \\ \underline{\boxed{\textsf{Area of Chart Paper required by him is 550 } \sf cm^2.}} \\ \\ \Large{\mathfrak{\underline{Step-by-Step \: Explanation:}}} \\ \\ \sf Given, \\ \textsf{Radius of the base of the cylindrical kaleidoscope (r) = 3.5 cm} \\ \textsf{Height (Length) of kaleidoscope (h) = 25 cm} \\ \\ \textsf{Area of Chart Paper Required =} \\ \qquad \implies \textsf{Curved Surface Area of the kaleidoscope} \\ \qquad \implies \sf 2 \pi rh \\ \qquad \implies \sf 2 × \frac{22}{7} × 3.5 × 25 \\ \qquad \implies \sf 550 \: cm^2 \\ \\ \sf \large \underline{Thanks \: ..!!!}$

Answer 2

given

h = 25cm

r = 3.5

find

the requirements of chart paper

Solution

in the given figure cylinder surface area= 2πrh

the requirement of paper = 2*22*3.5*25/7= 550cm^2