Physics, asked by sahilshaikhd617, 6 months ago

SW
v. When a p-n-p transistor is operated in saturation region, then its
(A) the base-emitter junction is forward biased and base-collector junction is reverse biased
(B) both the base-emitter junction and base-collector junction are reverse biased
(C) both the base-emitter junction and base-collector junction are forward biased
(D) the base-emitter junction is reverse biased and base-collector junction is forward biased​

Answers

Answered by s1240sahil19789
4

Answer:

a)As shown in the above figure, the emitter to base junction is forward biased and the collector to base junction is reverse biased. Forward bias on the emitter to base junction causes the electrons to flow from N type emitter towards the bias. This condition formulates the emitter current (IE).

b)The collector is kept at a higher potential than base or emitter so that the collector can attract all the electrons from emitter in case of a npn transistor as an example. For this to happen the collector base junction is reverse biased.

c)Saturation region is one in which both Emitter Base and Base Collector junctions of the transistor are forward biased. In this region high currents flows through the transistor, as both junctions of the transistor are forward biased and bulk resistance offered is very much less.

d)When the base emitter junction is forward biased and the collector/base junction is reverse biased, the electrons move from the n-type region towards the p-type region and the holes move towards the n-type region. ... When a current flows between the base and emitter, electrons leave the emitter and flow into the base.

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