Math, asked by venkadesh7379, 1 year ago

Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?
A) 20
B) 41
C) 26
D) 33

Answers

Answered by Anonymous
0
Given P = 54 and M = 80

According to the question,

Let ‘A’ years ago, M = 3P

=> M - A/P - A = 3

=> 80 - A = 3(54 - A)

=> 80 - A = 162 - 3A

=> 2A = 82

=> A = 41

Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age.

Hence, at the age S = 13 and M = 39
Answered by Anonymous
0
Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?

A) 20
B) 41
C) 26
D) 33

Answer:   B) 41 

Read Description:

Given X = 54 and Y = 80

According to the question,

Let ‘A’ years ago, Y = 3P

=> Y - A/X - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41

Therefore, A = 41 years ago 
Sweety’s mother was 3 times of Sweety’s age.

Hence, at the age S = 13 and Y = 39.
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