Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?
A) 20
B) 41
C) 26
D) 33
Answers
Answered by
0
Given P = 54 and M = 80
According to the question,
Let ‘A’ years ago, M = 3P
=> M - A/P - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age.
Hence, at the age S = 13 and M = 39
According to the question,
Let ‘A’ years ago, M = 3P
=> M - A/P - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age.
Hence, at the age S = 13 and M = 39
Answered by
0
Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?
A) 20
B) 41
C) 26
D) 33
Answer: B) 41
Read Description:
Given X = 54 and Y = 80
According to the question,
Let ‘A’ years ago, Y = 3P
=> Y - A/X - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago
Sweety’s mother was 3 times of Sweety’s age.
Hence, at the age S = 13 and Y = 39.
A) 20
B) 41
C) 26
D) 33
Answer: B) 41
Read Description:
Given X = 54 and Y = 80
According to the question,
Let ‘A’ years ago, Y = 3P
=> Y - A/X - A = 3
=> 80 - A = 3(54 - A)
=> 80 - A = 162 - 3A
=> 2A = 82
=> A = 41
Therefore, A = 41 years ago
Sweety’s mother was 3 times of Sweety’s age.
Hence, at the age S = 13 and Y = 39.
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