Question

Swena is 29 years younger than her father and 26 years older than her son. The sum of the ages
of all three is 135 years. What is the age of each one of them?​

Answer 1

let, son's age = x

Swena's age = (x+26)

Swena's father's age = (x+26+29)

According to question,

Sum of their age,

x+(x+26)+(x+26+29) = 135

(x+x+26+x+26+29) = 135

(3x+81) = 135

3x = 135-81

x = 54/3

x = 18

So,

Son's age = 18

Swena's age = 44

Swena's father's age = 73.

Answer 2

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Answer:

➻ The age of Sweena's son = 18 years

➻ The age of Sweena = 44 years

➻ The age of Sweena's father = 73 years

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Step-by-step explanation:

Given:

➻ Sweena is 29 years younger than her father.

➻ 26 years older than her son .

The sum of the ages of all three is 135 .

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To Find:

➻ Their ages.

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Solution:

↦ Let the age of Sweena's son = x

↦ Sweena's age = x + 26

↦ Sweena's father age = (x+26+29) = x + 55

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According to question:

⇒ x + (x+26) + (x+55) = 135

⇒ x + x+26 + x+55 = 135

⇒ 3x + 81 = 135

⇒ 3x = 54

⇒ x = 54 / 3

⇒ x = 18

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↦ The age of Sweena's son = 18 years

↦ The age of Sweena = x + 26

⇒ 18 + 26

⇒ 44 years

The age of Sweena's father = x + 55

⇒ 18 + 55

⇒ 73 years

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Sum of all ages:

18 + 44 +73 = 135

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