Question

System is shown in the figure. Assume that cylinder remains in contact with the two wedges. The
velocity of cylinder​

Answer 1

Answer:

Velocity of cylinder = V = √7u

Explanation:

We divide the velocity V in in two components; Vx(horizontal) and Vy(vertical);

As the cylinder will remain in contant with wedge A;

Vx = 2u

As it also remain in cotanct with wedge B;

U sin 30 = Vy cos 30 – Vx sin 30

U sin 30 + Vx sin 30 = Vy cos 30

Vy = Vx (sin30/cos 30) + u (sin30/cos30)

Vy = Vx tan 30 + u tan 30

As Vx = 2u

So equation becomes;

Vy = 3u tan 30

Vy = √3u

V = √(〖Vx〗^2+〖Vy〗^2 )  

V = √(〖2u〗^2+3u)  

V = √7u

Answer 2

Answer:

Let velocity of cylinder is V m/s.

Its component Vx and Vy.

Vx=2u m/s.

Vy=?

Explanation: