t+1 is factor of 4t³+4t²-t-1
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Hey! Here is ur answer...
Since (t + 1) is a factor
So, t + 1 = 0
t = -1 (Put this in given equation)
Given, 4t^3 + 4t^2 - t - 1
= [4(-1)^3]+ [4(-1)^2] - (-1) - 1
= -4 + 4 + 1 - 1
= 0
Since, t = -1 satisfies the given equation
Therefore, (t + 1) is a factor of the given equation.
Hope this helps u...Plz mark it as brainliest... :)
Since (t + 1) is a factor
So, t + 1 = 0
t = -1 (Put this in given equation)
Given, 4t^3 + 4t^2 - t - 1
= [4(-1)^3]+ [4(-1)^2] - (-1) - 1
= -4 + 4 + 1 - 1
= 0
Since, t = -1 satisfies the given equation
Therefore, (t + 1) is a factor of the given equation.
Hope this helps u...Plz mark it as brainliest... :)
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