Question

t^2+8t+18 find zeros and coefficient

Answer 1

by splitting the middel term
we get

p(x)= t^2+8t+18=0. [since p(x)=0]

=> t^2+6t+3t+18=0

=> t(t+6)+3(t+6)=0

=> (t+3)(t+6)=0

=> t+3=0. or. t+6=0
=>. t= -3. or. t= -6

hence, give quadratic equation's zeroes are -3 & -6

I hope it helped you
please make as brainlist....