Math, asked by cutter2020, 11 months ago

t^2-t-4=0 , find roots of this eqn​

Answers

Answered by bindusri1828
1

Answer:

 {t}^{2}  - t - 4 = 0 \\ t =  \frac{ - b( + )(  - ) \sqrt{ {b}^{2}  - 4ac} }{2a}  \\

but here under root b^2 -4ac is negative

so it doesn't have real roots


cutter2020: So, find the non-real roots
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