Question

t^2-t-4=0 , find roots of this eqn​

Answer 1

Answer:

${t}^{2} - t - 4 = 0 \\ t = \frac{ - b( + )( - ) \sqrt{ {b}^{2} - 4ac} }{2a}$

but here under root b^2 -4ac is negative

so it doesn't have real roots