t-(2t+5)-5 (1-2t)=2 (3+4t)-3 (t-4) can anyone solve this equation
Answers
Answered by
282
t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4)
t-2t-5-5+10t=6+8t-3t+12
9t-10=18+5t
9t-5t=18+10
4t=28
t=7
t-2t-5-5+10t=6+8t-3t+12
9t-10=18+5t
9t-5t=18+10
4t=28
t=7
Emerald1st:
thanks for helping
Answered by
96
Answer:
Value of t = 7
Step-by-step explanation:
Given simple equation:
t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4)
=> t - 2t - 5 - 5 + 10t = 6 + 8t - 3t + 12
=> t - 2t + 10t - 8t + 3t = 6 + 12 + 5 + 5
=> (1-2+10-8+3)t = 28
=> 4t = 28
/* Divide each term by 4 , we get
=> t = 7
Therefore,
Value of t = 7
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