Question

t^3-2t^2-15t find zeros of this cubic equation. plzzz fast

Answer 1

➡HERE IS YOUR ANSWER⬇

${t}^{3} - 2 {t}^{2} - 15t \\ \\ = t( {t}^{2} - 2t - 15) \\ \\ = t( {t}^{2} - 5t + 3t - 15) \\ \\ = t( \: t(t - 5) + 3(t - 5) \: ) \\ \\ = t(t - 5)(t + 3)$

Hence, the zeroes of the cubic equation are

0, 5 and (-3).

⬆HOPE THIS HELPS YOU⬅

Answer 2

Given: t³ - 2t² - 15t

➟ t³ - 5t² + 3t² - 15t

➟ t (t² - 5t + 3t -15)

➟ t [t(t - 5) + 3(t - 5)]

➟ t = 0, t = 5, t = -3

Hence, the zeroes are α = 0, β = 5 & γ = -3.