Question

T/4
sin x cOS X
dx
0
cos* x + sin4
1 x​

Answer 1

Answer:

(2sinx−cosx)(1+cosx)=sin  2  x

⇒2sinx(1+cosx)−cosx−cos  

2  x−sin  2  x=0

⇒2sinx(1+cosx)−cosx−1=0

⇒2sinx(1+cosx)−1(1+cosx)=0

⇒(2sinx−1)(1+cosx)=0

⇒sinx=  2

1  or cosx=1

Step-by-step explanation:

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