Question

t^5 * 6^2* 2^5 / t^2 *3^3* 2^2 solve the following exponential problem

Answer 1

i cant, you need to put what *t* means

¯\_(ツ)_/¯

Answer 2

$\: \: \: \: \: \frac{ {t}^{5} \times {6}^{2} \times {2}^{5} }{ {t}^{2} \times {3}^{3} \times {2}^{2} } \\ = \frac{ {t}^{5} \times {(2 \times 3)}^{2} \times {2}^{5} }{ {t}^{2} \times {3}^{3} \times {2}^{2} } \\ = \frac{ {t}^{5} \times {2}^{2} \times {3}^{2} \times {2}^{5} }{ {t}^{2} \times {3}^{3} \times {2}^{2} } \: \: \: ... \: {(ab)}^{m} = {a}^{m} {b}^{m} \\ = \frac{ {t}^{5} \times {3}^{2} \times {2}^{2 + 5} }{ {t}^{2} \times {3}^{3} \times {2}^{2} } \: \: \: ... \: ( {a}^{m } . {a}^{n} = {a}^{m + n} ) \\ = {t}^{5 - 2} \times {3}^{2 - 3} \times {2}^{2 + 5 - 2} \: \: \: ...( \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} ) \\ = {t}^{3} \times {3}^{ - 1} \times {2}^{5} \\ = \frac{ {t}^{3} \times {2}^{5} }{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: ... \: ( {a}^{ - 1} = \frac{1}{a}) \\ = \frac{ {t}^{3} \times 32 }{3} \\ = \frac{32 {t}^{3} }{3}$