Question

T is a positive integer of 5 digits.It is greater than 70000 but less than 80000.It is the square of an odd integer.The product of the digits of t is 336.The thousand digit less than the hundreds digit two of tge digits are equal.. Tge sum of tge digits of t is

Answer 1

Answer:

19

Step-by-step explanation:

√70000 = 264.5

√80000 = 282.8

=>     265² ≤     T  ≤ 281²   (as its square of an odd integer)

                                Product of digits

265² = 70225            0

267² = 71289             1008

269² = 72361             252

271² =  73441             336

273² = 74529             2520

275² = 75625             2100

277² = 76729              5292

279² =  77841              1568

281² =  78961               3024

T = 73441    

Two digits are Equal)\

thousand Digit 3 < Hundred digit 4

7 * 3 * 4 * 4 * 1 = 336  

Square of 271  (odd integer)

lies between  70000 and  80000

Hence Satisfies all condotion

T = 73441

Sum of Digits  = 7 + 3 + 4 + 4 + 1  = 19

Answer 2

Answer:19

Step-by-step explanation:

19