Question

T.s.a of cuboid whose l=20cm,b=15cm,h=8cm

Answer 1

Answer:

Step-by-step explanation:

TSA of cuboid is 2(lb+bh+hl)

2(20×15+15×8+8×20)

2(300+120+160)

2(420+160)

2×580

1160

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{T.S.A\:of\:cuboid=1160\:cm}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{given : }} \\ : \implies \text{Length(l) = 20 \: cm} \\ \\ : \implies \text{Breadth(b) = 15\: cm} \\ \\ : \implies \text{Height(h) = 8 \: cm} \\ \\ \red{ \underline \bold{to \: find : }} \\ : \implies \text{T.S.A \: of \: cuboid = ? }$

• According to given question :

$\bold{as \: we \: know \: that} \\ : \implies \text{T.S.A \: of \: cuboid} = 2(lb + bh + hl) \\ \\ : \implies \text{T.S.A \: of \: cuboid} = 2(20 \times 15 + 15\times 8 + 8 \times 20) \\ \\ : \implies \text{T.S.A \: of \: cuboid} = 2(300 + 120 + 160) \\ \\ : \implies \text{T.S.A \: of \: cuboid} = 2 \times 580 \\ \\ \green{: \implies \text{T.S.A \: of \: cuboid = 1160 \:{cm}}^{2} } \\ \\ \purple {\text{some \: formula \: related \: to \: this \: topic}} \\ \pink {\circ \: \text{L.S.A\: of \: cuboid = }2(l + b) \times h} \\ \\ \pink {\circ \: \text{Volume \: of \: cuboid = }l \times b \times h}$