Question

❥ᑌᑎTᗩᖇY ᗰᗴTᕼOᗪ

If 20 workers can do two-thirds of a piece of work in 50 days,what fraction of the work can be done by 12 workers in 60 days?

:ᑭᒪᘔ ᗪOᑎ'T GIᐯE ᑌʂɛƖɛʂʂ ᗩᑎʂ....(Iᴛ's ᴀ ʜᴜᴍʙʟᴇ ʀᴇǫᴜᴇsᴛ)​

Answer 1

Answer:

$\sf\large\underline\red{AnSWEr}$

20 men complete one-third of a work in 20 days

Part of work completed by 20 m in 20 days = (1/3)

Part of work completed by 20 m in 1 days = (1/3)(1/20)

Part of work completed by 1 m in 1 days = (1/3)(1/20)(1/20) = (1/1200)

Let n be the additional men required to finish the work in 25 more days.

Thus,

part of completed work + part of work to be completed in 25 days = 1

(1/3) + (20+n) x 25 x (1/1200) = 1

(1/3) + (1/48)(20+n) = 1

n = 12

$\sf\large\underline\green{12}$

more men should be employed to finish the rest of the work

Answer 2

20 men complete one-third of a work in 20 days

Part of work completed by 20 m in 20 days = (1/3)

Part of work completed by 20 m in 1 days = (1/3)(1/20)

Part of work completed by 1 m in 1 days = (1/3)(1/20)(1/20) = (1/1200)

Let n be the additional men required to finish the work in 25 more days.

Thus,

part of completed work + part of work to be completed in 25 days = 1

(1/3) + (20+n) x 25 x (1/1200) = 1

(1/3) + (1/48)(20+n) = 1

n = 12

12

more men should be employed to finish the rest of the work