Physics, asked by shreyashree53, 1 year ago

T1 and T2 in figure are​

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Answered by Anonymous
5

solution

t1 =  \frac{5 + 7}{3 + 5 + 7}   \times 120=  \frac{12}{15}  \times 120  \\ =  \frac{4}{5}  \times 120n  \\  = 4 \times 24n = 96n

and

t2 =  \frac{7}{3 + 5 + 7}  \times 120n \\  =  \frac{7}{15}  \times 120n \\  = 7 \times 8n = 56n

option (c)96 N,56N

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