Question

t² - 2t - 1 factorise the term

Answer 1

♡Answer♡:-

${t}^{2} - 2t + 1 \\ = {t}^{2} - (1 + 1)t + 1 \\ = {t}^{2} - t - t + 1 \\ = t(t - 1) - 1(t - 1) \\ = (t - 1)(t - 1)$

Now,

$(t - 1) = 0 \: \: and \: \: (t - 1) = 0 \\ t = 1 \: \: and \: \: t = 1(ans)$

It may help you.

♡Thank you♡