Question

t²+4t-5=0 how to solve this using formula step by step

Answer 1

hope you understand
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Answer 2

Hello friend!!!!.....Here is ur answer

${t}^{2} + 4t - 5 = 0 \\ \\ {t}^{2} + 5t - t - 5 = 0 \\ \\ t(t + 5) - 1(t + 5) = 0 \\ \\ (t + 5)(t - 1) = 0 \\ \\ t = - 5 \: \: \: \: and \: \: \: t = 1$

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