Question

तीन लगातार सम संख्याओं का योग 36 है ​

Answer 1

Answer:

let 1st no. be x

2nd no.= x+2

3rd no.=x+2+2=x+4

a/q x+x+2+x+4=36

3x+6=36

3x=36-6

3x=30

x=10

1st no. is 10

2nd no. is 12

3td no.14