Question

Take a = 5cm , b = 3cm : . AB = a + b = Area of ABCD = ( a + b ) ² = Area of each rectangle = ab = Area of square PQRS = ( a - b ) ² = sq . units . Area ABCD = 4 ( area of rectangular piece ) + Area of square PQRS < = 4 ( or > 4 ( i.e. ( a + b ) ² > 4 ab a + b 2 > √ab units . or sq . units . sq . units . ( a + b ) * > AM > GM > ab

Answer 1

Answer:

a + b

5 + 3

8 cm

abcd = (a+ b) square

8 square

16

pqrs = ( a - b) square

5-3 = 2

2*2 = 4sq.

4 + 16 + 4 < = 4

24 < = 4

Answer 2

Given:

a=5 cm,b=3 cm

Step-by-step explanation:

$AB = a + b$

       $=5+3$

       $=8$

Area of ABCD$= ( a + b )^{2}$

                $=(5+3)^{2}$

                $=8^{2}$

               $=64$

Area of each rectangle $= ab$

                                      $=5*3$

                                        $=15$

Area of square PQRS $= ( a - b ) ^{2}$

                                     $=(5-3)^{2}$

                                     $=2^{2}$

                                     $=4$= sq . units

Area ABCD = 4 ( area of rectangular piece ) + Area of square PQRS < = 4

                   $=4(15)+4$

                   $=64$

$( a + b ) ^{2} > 4 ab( a + b )^{2} > \sqrt{ab}$ units

$=(5+3)^{2} > 4(15)(64)>\sqrt{15}$ units

$=64>3840>3.8729$ units

.AB = a + b = Area of ABCD = ( a + b ) ² = Area of each rectangle = ab = Area of square PQRS = ( a - b ) ² = sq . units

$AB =8=64=15=4= sq . units$