Question

Take a clean copper wire and iron nail put copper wire in a solution of iron sulphate and iron nail in a solution of copper sulphate taken in test tube record your observation after 20 minutes in which test tube did you find the reaction has occurred on what basis you can say the reaction was actually taken place can you complete your observation on activity number 3.9 3.10 and 3.11 write a chemical equation

Answer 1

In test tube B THE reaction will take place
as iron is a High reactive than copper so it displace copper from copper sulphate solution
The reaction is :
CuSo4+Fe - FeSo4 + Cu
for test tube A doesn't any reaction takes place

Answer 2

The reaction will occur in test tube B .

• The reactivity of iron (Fe) is more than that of copper (Cu) . So, reaction will takes place in test tube B .
• In test tube colour of the solution will change from blue to green due to formation of iron sulphate .
• The chemical equation is ->

                  $CuSO_{4} + Fe -> FeSO_{4} + Cu$