Question

take a siluitable set and prove the properly AUB=BUA​

Answer 1

Step-by-step explanation:

A U B = {x : x ϵ A or x ϵ B}

So, A U B = {2, 4, 6, 8, 10, 12},

here the common elements are not repeated.

Properties of (A U B)

Commutative law holds true as (A U B) = (B U A)

Associative law also holds true as (A U B) U {C} = {A} U (B U C)