Take a soft wire. Measure it's length. Make a square, a circle, an equilateral triangle and find their circumference perimeters. Verify that they are equal.
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Let the perimeter be p, radius of circle be r and side length of square and triangle be a and b respectively.
p=2πr=4a=3b
so r=p2π,a=p4,b=p3
area of circle = πr2=p24π
area of square = a2=p216
area of triangle = 3√4b2=p2123√
Since 4π<16<12 3–√ , area of circle > square > triangle.
In fact, for a given perimeter, a circle has the largest area of all possible figures
Step-by-step explanation:
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