Question

Take C1=4·0 μF and C2=6·0 μF in figure (31-E3). Calculate the equivalent capacitance of the combination between the points indicated.
Figure

Answer 1

The equivalent capacitance of the combination between the points indicated is equal to the$2.4 \mu F$.

Explanation:

Step 1:

From the given figure, consider two capacitors C1 & C2 are connected in series.

Step 2:

We know that when capacitors are connected in series, the total capacitance is less than any one of the capacitors individual capacitances.

If more than one capacitors are joined in series, the overall effect is that of a single (equivalent) capacitor having the total of the plate spacing’s of the individual capacitors.

Step 3:

So from the above figure we can say that capacitors are connected in series and $\mathrm{Ceq}=\mathrm{ClC} 2 / \mathrm{Cl}+\mathrm{C} 2$

$C=4 \times 6 / 4+6=2.4 \mu F$

Therefore the equivalent capacitance of the combination between the points indicated is equal to the $2.4 \mu F$