Question

The plates of a parallel-plate capacitor are made of circular discs of radii 5⋅0 cm each. If the separation between the plates is 1⋅0 mm, what is the capacitance?

Answer 1

Answer:

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Answer 2

The capacitance of parallel-plate capacitor is equal to the 6.95 X 10-5 μF

Explanation:

• Considering the Capacitor connected in a circuit the equivalent capacitance is given by

C = €A/d

• Where € = dielectric constant of the capacitor
• A= Area of the plates
• d= distance between the plates  

Given,  Area of the plates = πr2 = π (5 $\times$ 10-2)2

d= 1⋅0 mm = 1$\times$10-3

We know the value of dielectric constant = 8.853 $\times$ 10-12

By substituting the values into above formula

C= 8.853 $\times$ 10-12 $\times$ 3.14 $\times$ (5 $\times$ 10-2)2/1 $\times$ 10-3

• After solving the above equation, we can get C is 6.95 $\times$ 10-5 μF
• Hence, we can say that the capacitance of parallel-plate capacitor is equal to the 6.95 $\times$ 10-5 μF