Take g=9.8ms^-2 on the surface of the earth, massof the earth (M)=-6 × 10²⁴kg, radius of the earth (R)=6,400km
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Answer:
M= mass of earth
R= radius of earth =6400km=6.4×106m
g1= acceleration due to gravity on the surface of earth =9.8m/s2
h= height above the surface of earth 480km=0.480×106m
g2= acceleration due to gravity above the surface of earth=?
acceleration due to gravity on the surface is given
g1=R2GM----------------------------(1)
acceleration due to gravity above the surface is given:
g2=(R+h)2GM------------------(2)
g1g2=R2GM(R+h)2GM
g1g2=(R+h)2R2
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