Math, asked by boypro015, 1 month ago

Take Seema’s present age be x years.

a. Seema’s father’s age is 2 years more than 4 times seema’s age. What is her father’s age?

b. Seema’s brother is 4 years younger than Seema’s age. What is her brother’s age?

c. What will be her age 11 years from now?​

Answers

Answered by leharbafna2030
1

Answer:

a. 42 years

b. 6 years

c. 21 years

Step-by-step explanation:

a. Age of Seema: 10 years

a. Age of Seema: 10 yearsFour times of Seema's age: 10 × 4 = 40 years

a. Age of Seema: 10 yearsFour times of Seema's age: 10 × 4 = 40 yearsFather's age: 2 years more than Seema's age (40+2=42)

Ans a. 42 years

b. Age of Seema: 10 years

b. Age of Seema: 10 yearsBrother's age: 4 years younger (10-4= 6 )

Ans b. Brother's age will be 6 years.

c. Age of Seema: 10 years

c. Age of Seema: 10 yearsAge of seema after 11 years: 10+ 11= 21

Ans c. Age of Seema after 11 years will be 21 years.

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