Take Seema’s present age be x years.
a. Seema’s father’s age is 2 years more than 4 times seema’s age. What is her father’s age?
b. Seema’s brother is 4 years younger than Seema’s age. What is her brother’s age?
c. What will be her age 11 years from now?
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Answer:
a. 42 years
b. 6 years
c. 21 years
Step-by-step explanation:
a. Age of Seema: 10 years
a. Age of Seema: 10 yearsFour times of Seema's age: 10 × 4 = 40 years
a. Age of Seema: 10 yearsFour times of Seema's age: 10 × 4 = 40 yearsFather's age: 2 years more than Seema's age (40+2=42)
Ans a. 42 years
b. Age of Seema: 10 years
b. Age of Seema: 10 yearsBrother's age: 4 years younger (10-4= 6 )
Ans b. Brother's age will be 6 years.
c. Age of Seema: 10 years
c. Age of Seema: 10 yearsAge of seema after 11 years: 10+ 11= 21
Ans c. Age of Seema after 11 years will be 21 years.
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