Take the uniform accelartion near the surface of earth to be 9.8 ms 2 for a free fall. What is
the velocity of a body at the end of two second of free fall, if the initial velocity is zero?
(8=9.8m/s²)
please
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a = 9.8 m/s square
u = 0 m/s
t = 2 sec
v = ?
as we already know......
v = u + at
=> v = 0 + (9.8 × 2)
=> v = 19.6 m/s
hope it's helpful.....!!
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