Taking ¢ = 30° , verify that :
• sin 3¢ = 3 sin¢ - 4 sin³¢.
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Answered by
15
When theta = 30° , we have 3 theta = 3 × 30 = 90°.
Sin 3 Theta = Sin90° = 1
And,
3 Sin theta - 4 Sin³ theta
=> 3 Sin30° - 4 Sin³ 30°
=> [ 3 × 1/2 - 4 × (1/2)³ ]
=> ( 3/2 - 4 × 1/8 )
=> ( 3/2 - 1/2 )
=> ( 3 - 1 ) /2
=> 2/2
=> 1
Therefore,
Sin 3Theta = 3 Sin theta - 4 Sin³ theta..
Sin 3 Theta = Sin90° = 1
And,
3 Sin theta - 4 Sin³ theta
=> 3 Sin30° - 4 Sin³ 30°
=> [ 3 × 1/2 - 4 × (1/2)³ ]
=> ( 3/2 - 4 × 1/8 )
=> ( 3/2 - 1/2 )
=> ( 3 - 1 ) /2
=> 2/2
=> 1
Therefore,
Sin 3Theta = 3 Sin theta - 4 Sin³ theta..
DevilDoll12:
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1
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