Taking an appropriate scale find the position of the image of an object of finite size placed
at a distance of 8cm in front of a convex lens of focal length 10 cm. Write down the
characteristics of the image formed.
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Answer:
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Explanation:
Fromlensformulaeweget
f
1
=
v
1
−
u
1
f
1
+
u
1
=
v
1
Now object distance from optic centre=−8cm
and focal length=10cm
v
1
=
10
1
−
8
1
v=−40cm
Since−ve sign the image will form in front of the lens and will virtual,enlarge and erect.
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