Question

taking common 9x square - 6ax=​

Answer 1

Step-by-step explanation:

Given 9x

2

−6ax+a

2

−b

2

=0

⇒9x

2

−6ax+(a−b)(a+b)=0

⇒9x

2

−3x(a−b)−3x(a+b)+(a−b)(a+b)=0

⇒3x[3x−(a−b)]−(a+b)[3x−(a−b)]=0

⇒[3x−(a−b)][3x−(a+b)]=0

3x−(a−b)=0

3x=a−b

x=

3

a−b

3x−(a+b)=0

3x=(a+b)

x=

3

a+b

∴x=

3

(a−b)

or x=

3

(a+b)