Taking moon's period of revolution about the earth as 30 days calculate its distance from the earth.
(G = 6.7 × 10^-11)
mass of earth = 6×10^24kg
Final Answer should be :- 4.8×10^5
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The Kepler's law of planetary motion says,
T^2= 4π^2 R^3/GM
Where T is the time period of revolution, R is the radius of moon's orbit, M is the mass of the planet (Earth), G is the universal gravitational constant.
We have,
T = 30 days = 2592000 s
G = 6.67 X 10-11 N(m/kg)2
M = 5.97 X 10-24 kg
Therefore,
2592000^2= 4*3.14^2 *R^3/6.67*10^-11 * 5.97*10^24
R=4.8*10^5
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