Question

taking out the ce
-15
3
+3
-5
Ex. (4) Find the fa
Solution : 2v2 - 4y - 30
= 2(v2 - 2y - 15)
= 2072 - 5y + 3y - 15)
= 2 [V0Y - 5) + 3(y – 5)]
= 209 - 5)(y + 3)
38
3
Practice Set 6.1
1. Factorise.
(1) x² + x + 18
(4) 5y + 5y - 10
(7) m? - 23m + 120
(10) 2r² + x - 45
(2) r- 10x + 9
(5) p2 - 2p - 35
(8) m2 - 25m + 100
(11) 20x2 - 26x + 8
(3) y2 + 24y + 144
(6)p? - 7p - 44
(9) 3x2 + 14x + 15
(12) 44x² - x - 3
Let's learn.
Factors of QP +63
We know that, (a + b)' = + 3a²b + 3ab² + b), which we can write as​

Answer 1

Answer:

taking out the ce -15 3 +3 -5 Ex. (4) Find the fa Solution : 2v2 - 4y - 30 = 2(v2 - 2y - 15) = 2072 ... - did not match any documents.

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