Math, asked by jayantkumardga, 3 months ago


tan 0 +
1/tan0
=
sec0 cosec 0​

Answers

Answered by mdshafinkhans
0

Answer:

L.H.S=R.H.S

Step-by-step explanation:

L.H.S= tan0 + 1/tan0

= (sin0/cos0)+ (cos0/sin0)

= ((sin0)^2+ (cos0)^2)/(cos0sin0)

= 1/(cos0sin0) [(sin0)^2 + (cos0)^2 = 1]

R.H.S= sec0cosec0

=(1/cos0)(1/sin0)

=1/(cos0sin0)

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