Question

The following figure shows the cross-section
ABCD of a swimming pool which is a
trapezium in shape.
B
If the width DC, of the swimming pool is
6.4 m, depth (AD) at the shallow end is
80 cm and depth (BC) at the deepest end is
2.4 m, find its area of cross-section.​

Answer 1

Answer:

1/2*(0.8+2.4)*6.4

1024m²

Answer 2

Answer:10.24 m (the above one is almost correct perfectly just some mistakes)

Step-by-step explanation:

Area of trapezium is 1/2* Height * (a+b)

1/2*(0.8+2.4)*6.4

10.24 m²

if u want it in cm it will be 1024cm²

(Please mark me as brainliest and give a nice rating please)