Question

tan-1 2x/1-x2difference substitution
​

Answer 1

Answer:

Let x=tanθ

⇒y=tan

−1

[

1−tan

2

θ

2tanθ

]

y=tan

−1

(tan2θ)

y=2θ

y=2tan

−1

x

Differentiate w.r.t to x

dx

dy

=2[

1+x

2

1

]

⇒

dx

dy

=

1+x

2

.