Question

What mass of CH3COONa required to make 200 ml of 0.245 molar aqueous solution?

Answer 1

Answer:

4.01 g

Explanation:

0.245 M solution of CH3COONa = 0.245 moles of CH3COONa/1000 ml

No. of moles of CH3COONa in 200 ml = 0.049 moles

Molar mass of sodium acetate = 82.0245 g/mole

∴ mass of CH3COONa required = 82.0245× 0.049 = 4.019 g (approximate)