Question

tan¢+1/tan¢=2.find the valueof tan²¢+1/tan²¢

Answer 1

Let tan be equal to x
then, 
x + 1/x = 2
(x+1/x)^2= x^2 + 1/x^2 + 2
   
Then,
x^2 + 1/x^2 = 4 - 2 = 2

Hope this helps

Answer 2

Answer :

Given,

tan¢ + 1/tan¢ = 2

Now, squaring both sides, we get

(tan¢ + 1/tan¢)² = 2²

⇒ tan²¢ + (2 × tan¢ × 1/tan¢) + (1/tan¢)² = 4

⇒ tan²¢ + 2 + 1/tan²¢ = 4 [∵ tan¢ × 1/tan¢ = 1]

⇒ tan²¢ + 1/tan²¢ = 4 - 2

⇒ tan²¢ + 1/tan²¢ = 2

∴ tan²¢ + 1/tan²¢ = 2

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