tan 1, tan2, tan3.......................tan88 ,tan 89
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Ans=>
tan 1.tan 2. tan3. .... tan 45......tan 87.tan 88. tan89.
=>tan 1.tan 2.tan 3.......1............tan(90-3).tan(90-2).tan(90-1).
=>tan 1.tan 2.tan 3........1...........cot 3.cot 2.cot 1.
=>1.(Ans.)
tan 1.tan 2. tan3. .... tan 45......tan 87.tan 88. tan89.
=>tan 1.tan 2.tan 3.......1............tan(90-3).tan(90-2).tan(90-1).
=>tan 1.tan 2.tan 3........1...........cot 3.cot 2.cot 1.
=>1.(Ans.)
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1
Extending the to first 4 multiple and last 4 too:
tan1.tan2.tan3.tan4………tan86.tan87.tan88.tan89
Note convert first 4 tan to cot (by using trignomatrical ratio of complementary angle - tan(90-A)=cotA & cot(90-A)=tanA )
Now,
cot89.cot88.cot87.cot86…………tan86.tan87.tan88.tan89
We know that cotA×tanA=1
So,
cot89.tan89.cot88.tan88.cot87.tan87.cot86.tan86……………
1.1.1.1.………
Therefore, 1
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