tan-¹ (x/√1+x²) ka difference
Answers
Answered by
0
Step-by-step explanation:
Let x = tanθ
⇒θ = tan–¹ x
tan
1
(
x
+
√
1
+
x
2
)
=
tan
1
(
tan
θ
+
√
1
+
tan
2
θ
)
=
tan
1
(
tan
θ
+
√
sec
2
θ
)
=
tan
1
(
tan
θ
+
sec
θ
)
=
tan
1
(
sin
θ
cos
θ
+
1
cos
θ
)
=
tan
1
(
sin
θ
+
1
cos
θ
)
=
tan
1
⎛
⎜
⎜
⎝
2
sin
(
θ
2
)
cos
(
θ
2
)
+
sin
2
(
θ
2
)
+
cos
2
(
θ
2
)
cos
2
(
θ
2
)
−
sin
2
(
θ
2
)
⎞
⎟
⎟
⎠
=
tan
1
⎛
⎜
⎜
⎝
(
sin
(
θ
2
)
+
cos
(
θ
2
)
)
2
(
cos
(
θ
2
)
−
sin
(
θ
2
)
)
(
cos
(
θ
2
)
+
sin
(
θ
2
)
)
⎞
⎟
⎟
⎠
=
tan
1
⎛
⎜
⎜
⎝
cos
(
θ
2
)
+
sin
(
θ
2
)
cos
(
θ
2
)
−
sin
(
θ
2
)
⎞
⎟
⎟
⎠
=
tan
1
⎛
⎜
⎜
⎜
⎜
⎜
⎝
cos
(
θ
2
)
cos
(
θ
2
)
+
sin
(
θ
2
)
cos
(
θ
2
)
cos
(
θ
2
)
cos
(
θ
2
)
−
sin
(
θ
2
)
cos
(
θ
2
)
⎞
⎟
⎟
⎟
⎟
⎟
⎠
=
tan
1
⎛
⎜
⎜
⎝
1
+
tan
(
θ
2
)
1
−
tan
(
θ
2
)
⎞
⎟
⎟
⎠
=
tan
1
⎛
⎜
⎜
⎝
tan
(
π
4
)
+
tan
(
θ
2
)
1
−
tan
(
π
4
)
tan
(
θ
2
)
⎞
⎟
⎟
⎠
=
tan
1
(
tan
(
π
4
+
θ
2
)
)
=
π
4
+
θ
2
=
π
4
+
1
2
tan
−
1
x
Answered by
0
Answer:
i don't
know
which
class
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