Question

Tan^-1 x/y + Cot ^-1 x/y​

Answer 1

Answer:

Correct option is

B

−

x

y

xy=tan

−1

(xy)+cot

−1

(xy)=

2

π

⇒xy=

2

π

∴x

dx

dy

+y=0

⇒

dx

dy

=

x

−y

Answer 2

$\tan^{-1}( \frac{x}{y}) + \cot ^{-1} (\frac{x}{y} )$

$\sf \purple{we \: know \: that : }$

$\blue{ \boxed{\tan^{-1}( a) + \cot ^{-1} (a) = \frac{\pi}{2} }}$

$\orange{\therefore \tan^{-1}( \frac{x}{y}) + \cot ^{-1} (\frac{x}{y} ) = \frac{\pi}{2} }$

HOPE IT HELPS!