Tan 11π/3-2sin4π/6-3/4cosec^2*π/4+4cos^2*17π/6
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Answer:
Step-by-step explanation:
=tan
3
11π
−2sin
3
4π
−
4
3
csc
2
4
π
+4cos
2
6
17π
csc
4
π
=
2
=tan(3π+
3
2π
)−2sin
3
2π
−
4
3
(
2
)
2
+4cos
2
(2π+
6
5π
)
=tan
3
2π
−2sin(π−
3
π
)−
2
3
+4cos
2
(π−
6
π
)
=−tan(
3
π
)−2sin
3
π
−
2
3
+4cos
2
6
π
puting values
tan(
3
π
)=
3
sin
3
π
=
3
/2
cos
6
π
=
3
/2
=−
3
−2
2
3
−
2
3
+4(
4
3
)
=−
3
−
3
−
2
3
+3
=
2
3−4
3
=RHS
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