Math, asked by Sakshi123ss, 1 year ago

Tan=12/13 evalute 2sin cos /cos^2-sin^2

Answers

Answered by Anonymous
8
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solution:--

Tanθ=12/13
P/B=12/13
P=12 ; B=13
H=√144+169
H=√313
​Sinθ=P/H=12/√313 ; Cosθ=B/H=13/√313
​...2sinθ cosθ​ =2(12/√313)(13/√313)    
  cos2θ-sin​2θ    (13/√313)2-(12/√313)2
   312/313   
=   169-144
       313
=312/25
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