Math, asked by devrishabh3387, 11 months ago

tan^2(A) / 1 + tan^2(A) = cos2A
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Answers

Answered by ahsanatminshin
2

L.H.S.

tan2A/1+tan2A

tan2A/1+(sec2A-1)

tan2A/sec2A

sin2A/cosA/1/cosA

sin2A

1+cos2A

cos2A=R.H.S

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Answered by khushichoudhary30
0

Answer:

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