tan^2 + cos^2 =1 plz solve it with the explanation
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Answered by
0
Answer:
0°
Step-by-step explanation:
=> tan²A + cos²A = 1
=> tan²A = 1 - cos²A
=> tan²A = sin²A
=> (sinA/cosA)² = sin²A
=> sin²A/cos²A = sin²A
=> 1/cos²A = 1
=> 1 = cos²A
=> 1 = cosA ,assuming cosA is lying in [0,90°]
=> cos0° = cosA
=> 0° = A
Answered by
1
Answer:
Step-by-step explanation:
Starting from the right hand side:
tan2(x)+cos2(x)−1=
=tan2(x)+cos2(x)−sin2(x)−cos2(x)
=tan2(x)−sin2(x)
=sin2(x)(sec2(x)−1)
=sin2(x)tan2(×)
=tan2(x)sin2(x)
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